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Commutative Algebra I
Commutative Algebra I

... Exercise 1.7. Let S be a commutative ring and R a subring of S. Let α1 , . . . , αn ∈ S be algebraically independent over R. Show that the subalgebra R[α1 , . . . , αn ] is isomorphic to the polynomial ring R[X1 , . . . , Xn ]. 1.2. Zero–divisors, Nilpotent and Unit Elements An element a of a ring R ...
Introduction The following thesis plays a central role in deformation
Introduction The following thesis plays a central role in deformation

... paper is to give a precise formulation of (∗) using the language of higher category theory. Our main result is Theorem 6.20, which can be regarded as an analogue of (∗) in the setting of noncommutative geometry. Our proof uses a method which can be adapted to prove a version of (∗) itself (Theorem 5 ...
arXiv:1510.01797v3 [math.CT] 21 Apr 2016 - Mathematik, Uni
arXiv:1510.01797v3 [math.CT] 21 Apr 2016 - Mathematik, Uni

... In the case where R = k is a field, Sweedler’s finite dual coalgebra construction A• [22] of a kalgebra A provides an extension of the above construction to arbitrary algebras. The underlying vector space A◦ of A• is the subspace of A∗ consisting of those linear forms whose kernel contains a cofinit ...
Bare Bones Algebra, Eh!?
Bare Bones Algebra, Eh!?

... if we enlarged the codomain of the function to C, then the new function, from A to C, must be regarded as being different from γ, even though it has the same domain and the same ‘formula’. This is usually not done in calculus. But it is necessary for the adjective ‘surjective’ to be meaningful: the ...
PROJECTIVE MODULES AND VECTOR BUNDLES The basic
PROJECTIVE MODULES AND VECTOR BUNDLES The basic

... particular R(κ) cannot be isomorphic to Rn for finite n. See ch.2, 5.5 of [Cohn65].) Definition 1.1 (IBP). We say that a ring R satisfies the (right) invariant basis property (or IBP) if Rm and Rn are not isomorphic for m 6= n. In this case, the rank of a free R-module M is an invariant, independent ...
FORMAL PLETHORIES Contents 1. Introduction 3 1.1. Outline of the
FORMAL PLETHORIES Contents 1. Introduction 3 1.1. Outline of the

... a comodule over this plethory for any space X. Examples of spectra satisfying these conditions include Morava K-theories, integral Morava K-theories including complex K-theory, and more generally any theories E satisfying (1.1) such that E∗ is a graded PID or Dedekind domain. Theories like M U or E( ...
Modular Categories
Modular Categories

... are inverses of each other, we have a bijection HomA C (FA (X), FA (Y )) ∼ = HomC (A ⊗ X, Y ). Thus FA will in general not be full, and it can happen that FA trivializes an object X ∈ C in the sense of mapping it to a multiple of the unit object (A, m) of A C. The free A-modules form a full subcateg ...
Basic Modern Algebraic Geometry
Basic Modern Algebraic Geometry

... Condition 1.1.1.2 Composition of morphisms is associative, in the sense that whenever one side in the below equality is defined, so is the other and equality holds: (ϕ ◦ ψ) ◦ ξ = ϕ ◦ (ψ ◦ ξ) ...
Linear Algebra II
Linear Algebra II

... as the monic polynomial of smallest degree that has the matrix or endomorphism as a “root”. However, we need to know a few more facts about polynomials in order to see that this definition makes sense. 2.3. Lemma (Polynomial Division). Let f and g be polynomials, with g monic. Then there are unique ...
Linear Algebra I
Linear Algebra I

... as the monic polynomial of smallest degree that has the matrix or endomorphism as a “root”. However, we need to know a few more facts about polynomials in order to see that this definition makes sense. 2.3. Lemma (Polynomial Division). Let f and g be polynomials, with g monic. Then there are unique ...
Examples - Stacks Project
Examples - Stacks Project

... (using multi-index notation) such that for each d ≥ 0 there are only finitely many nonzero aI for |I| = d. The maximal ideal m0 ⊂ R∧ is the collection of f with zero constant term. In particular, the element f = x1 + x22 + x33 + . . . is in m0 but not in mR∧ which shows that (1) is false in this exa ...
Structured Stable Homotopy Theory and the Descent Problem for
Structured Stable Homotopy Theory and the Descent Problem for

... It is not hard to verify, using the above change of rings isomorphism, that this spectral sequence is just the Quillen-Lichtenbaum spectral sequence described above, converging to the homotopy groups of the homotopy fixed point set of the GF -action on KF . Given any morphism of S-algebras A → B, it ...
A proof of the multiplicative property of the Berezinian ∗
A proof of the multiplicative property of the Berezinian ∗

... T . As a consequence, by the uniqueness up to unique isomorphism of the tensor product we have T ∼ = V ⊗ W .¤ Proposition 2.1.7. Let V and W supervector spaces, then V ⊗W exists Proof. Consider the set G = (V0 ∪ V1 ) \ {0} × (W0 ∪ W1 ) \ {0}. Let S a supervector space. Define a parity map p : G −→ Z ...
Selected HW solutions
Selected HW solutions

... second countable and Hausdorff. The first of these follows since it is a quotient of a second countable space. For Hausdorff, note that if [z1 ], [z2 ] ∈ Uj for some j, then they can be separated by disjoint open sets since the same is true of ϕj (z1 ), ϕj (z2 ) ∈ Cn . So we consider the case where ...
Modules and Vector Spaces
Modules and Vector Spaces

... (1) If R is any ring then the R-submodules of the R-module R are precisely the left ideals of the ring R. (2) If G is any abelian group then G is a Z-module and the Z-submodules of G are just the subgroups of G. (3) Let f : M → N be an R-module homomorphism. Then Ker(f ) ⊆ M and Im(f ) ⊆ N are R-sub ...
Representation Theory
Representation Theory

... Note that the equality makes sense even if φ is not invertible, in which case it is just called an intertwining operator or G-linear map. However, if φ is invertible, we can write instead ρ2 = φ ◦ ρ1 ◦ φ−1 , ...
TRANSLATION FUNCTORS AND DECOMPOSITION NUMBERS
TRANSLATION FUNCTORS AND DECOMPOSITION NUMBERS

... to [EQ16] where the Schur-Weyl dual quantum group for sl2 at q = i is categorified using the concept of p-dg categories. As an application of this categorical Temperley-Lieb algebra action we deduce in Theorem 9.1.2 a description of the blocks in Fn with the action of the translation functors (Corol ...
(pdf)
(pdf)

... our minimal left ideal L satisfies D = L ∼ = D , since for any ring R and any i > 0 Mi (R) has a simple left ideal isomorphic to R. But then we have that D ∼ = EndA (Dn ) ∼ = EndA (L) ∼ = EndA (D0m ) ∼ = D0 , so D ∼ = D0 . From here, we have that m = n, by dimension. This completes the uniqueness st ...
Hard Lefschetz theorem and Hodge-Riemann
Hard Lefschetz theorem and Hodge-Riemann

... canonical pairing (·, ·)Φ and had to make choices at each step. This ambiguity makes the proof unnecessarily heavy and hard to follow. Actually the results of this paper imply that the pairing in [9] is independent of the choices made and coincides with the canonical one. For completeness we present ...
Sheaves of Modules
Sheaves of Modules

... Proof. By Homology, Definition 5.1 we have to show that image and coimage agree. By Sheaves, Lemma 16.1 it is enough to show that image and coimage have the same stalk at every x ∈ X. By the constructions of kernels and cokernels above these stalks are the coimage and image in the categories of OX,x ...
670 notes - OSU Department of Mathematics
670 notes - OSU Department of Mathematics

... Use the handout. The concept of fundamental groups is, well, fundamental in topology. For example, one of the most important ways of studying a knot in R3 is to study the fundamental group of its complement. (Draw a picture.) Example. I won’t prove these claims, but I hope they appear plausible. A t ...
Chapter IV. Quotients by group schemes. When we work with group
Chapter IV. Quotients by group schemes. When we work with group

... is trivial, but if this holds the action need not be strictly free. For instance, with S = Spec(Q) as a base scheme, take G = ZS to be the constant group scheme defined by the (abstract) group Z, and take G! = Ga,S . We have a natural homomorphism f : ZS → Ga,S which, for Q-schemes T , is given on p ...
Sheaves of Modules
Sheaves of Modules

... Proof. By Homology, Definition 5.1 we have to show that image and coimage agree. By Sheaves, Lemma 16.1 it is enough to show that image and coimage have the same stalk at every x ∈ X. By the constructions of kernels and cokernels above these stalks are the coimage and image in the categories of OX,x ...
Hopf algebras, quantum groups and topological field theory
Hopf algebras, quantum groups and topological field theory

... 2. Denote by I+ (V ) the two-sided ideal of T (V ) that is generated by all elements of the form x ⊗ y − y ⊗ x with x, y ∈ V . The quotient S(V ) := T (V )/I+ (V ) with its natural algebra structure is called the symmetric algebra over V . The symmetric algebra is a Z+ -graded algebra, as well. It i ...
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Tensor product of modules



In mathematics, the tensor product of modules is a construction that allows arguments about bilinear maps (e.g. multiplication) to be carried out in terms of linear maps (module homomorphisms). The module construction is analogous to the construction of the tensor product of vector spaces, but can be carried out for a pair of modules over a commutative ring resulting in a third module, and also for a pair of a right-module and a left-module over any ring, with result an abelian group. Tensor products are important in areas of abstract algebra, homological algebra, algebraic topology and algebraic geometry. The universal property of the tensor product of vector spaces extends to more general situations in abstract algebra. It allows the study of bilinear or multilinear operations via linear operations. The tensor product of an algebra and a module can be used for extension of scalars. For a commutative ring, the tensor product of modules can be iterated to form the tensor algebra of a module, allowing one to define multiplication in the module in a universal way.
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