SQUARE ROOT EXTRACTOR - Measurement Technologies, Ltd
... The XZ2-S is an accurate 2 wire transmitter that produces an output current proportional to the square root of the applied input current. The standard input range is 4-20mA with an optional 10-50mA range. The unit is powered by the output current loop and requires a maximum of 6.3V. The XZ2-S is rev ...
... The XZ2-S is an accurate 2 wire transmitter that produces an output current proportional to the square root of the applied input current. The standard input range is 4-20mA with an optional 10-50mA range. The unit is powered by the output current loop and requires a maximum of 6.3V. The XZ2-S is rev ...
view - Meritnation
... Working – The spray comb is given a positive potential by high tension source. The positive charge gets sprayed on the belt. As the belt moves and reaches the sphere, a negative charge is induced on the sharp ends of collecting comb B2 and an equal positive charge is induced on the farther end of B2 ...
... Working – The spray comb is given a positive potential by high tension source. The positive charge gets sprayed on the belt. As the belt moves and reaches the sphere, a negative charge is induced on the sharp ends of collecting comb B2 and an equal positive charge is induced on the farther end of B2 ...
HCPL3700, An optocoupler with a difference
... voltage the output should go low. Low should be no more than 400 mV, typically 40 mV. Since the output is Open Collector we need a pullup resistor to VCC to see an output voltage. In the circuit shown with AC applied the output of the HCPL3700 should be constantly Low. This keeps the capacitor const ...
... voltage the output should go low. Low should be no more than 400 mV, typically 40 mV. Since the output is Open Collector we need a pullup resistor to VCC to see an output voltage. In the circuit shown with AC applied the output of the HCPL3700 should be constantly Low. This keeps the capacitor const ...
Meas_chap4-edit
... eliminated and ig can be written as: ig = Eg/(R+Rg) , where R is the effective resistance of the bridge circuit presented to the galvanometer and is given by: R = R1R4/(R1+R4) + R2R3/(R2+R3) The voltage presented at the terminals of the galvanometer Eg is: Eg = E[(R1/(R1+R4)-R2/(R2+R3)] Finally, sub ...
... eliminated and ig can be written as: ig = Eg/(R+Rg) , where R is the effective resistance of the bridge circuit presented to the galvanometer and is given by: R = R1R4/(R1+R4) + R2R3/(R2+R3) The voltage presented at the terminals of the galvanometer Eg is: Eg = E[(R1/(R1+R4)-R2/(R2+R3)] Finally, sub ...
What is an Operational Amplifier?
... 1) Amplifies small difference between two signals. 2) Output voltage will "switch" whenever the input voltage (at the inverting input) reaches the reference voltage Vref (at the non-inverting input) 3) Very useful for comparing signals and working with sensors ...
... 1) Amplifies small difference between two signals. 2) Output voltage will "switch" whenever the input voltage (at the inverting input) reaches the reference voltage Vref (at the non-inverting input) 3) Very useful for comparing signals and working with sensors ...
Datasheet - Technobots
... LP339 Ultra-Low Power Quad Comparator General Description The LP339 consists of four independent voltage comparators designed specifically to operate from a single power supply and draw typically 60 mA of power supply drain current over a wide range of power supply voltages. Operation from split sup ...
... LP339 Ultra-Low Power Quad Comparator General Description The LP339 consists of four independent voltage comparators designed specifically to operate from a single power supply and draw typically 60 mA of power supply drain current over a wide range of power supply voltages. Operation from split sup ...
Practice
... compressors), chemical energy (e.g., charging batteries), etc. As you can see from the list above, resistors play an important role in devices that rely on electricity. Relationship #2 Voltage tells us how much energy is available per charge. Current tells us the rate at which electrons’ energy pass ...
... compressors), chemical energy (e.g., charging batteries), etc. As you can see from the list above, resistors play an important role in devices that rely on electricity. Relationship #2 Voltage tells us how much energy is available per charge. Current tells us the rate at which electrons’ energy pass ...
How do series and parallel circuits work?
... 1. Each device in the circuit sees the full battery voltage. 2. Each device in the circuit may be turned off independently without stopping the current flowing to other devices in the circuit. ...
... 1. Each device in the circuit sees the full battery voltage. 2. Each device in the circuit may be turned off independently without stopping the current flowing to other devices in the circuit. ...
CIRCUIT FUNCTION AND BENEFITS
... bias current (21 pA typical). C9 is a compensation capacitor. The value of C9 for this application is 2.2 pF, which is optimized to compensate for the external output capacitance of the DAC. The capacitor C8 acts as an integrator to reduce noise, and a typical value of 47 pF is recommended. ...
... bias current (21 pA typical). C9 is a compensation capacitor. The value of C9 for this application is 2.2 pF, which is optimized to compensate for the external output capacitance of the DAC. The capacitor C8 acts as an integrator to reduce noise, and a typical value of 47 pF is recommended. ...
Test - Electro Tech Online
... circuit board with an oscilloscope I bought several years ago from a TV shop that was selling out. As shown in figure 2, I sketched the traces of the voltages I encountered and tried to line up the timing as best I could given my limited understanding of how these components work. The trace patterns ...
... circuit board with an oscilloscope I bought several years ago from a TV shop that was selling out. As shown in figure 2, I sketched the traces of the voltages I encountered and tried to line up the timing as best I could given my limited understanding of how these components work. The trace patterns ...
Current Transducer LF 305
... to applicable standards and safety requirements in accordance with the manufacturer’s operating instructions. ...
... to applicable standards and safety requirements in accordance with the manufacturer’s operating instructions. ...
4 – The Power BJT 3
... The Power Bipolar Junction Transistor (Part 3) Dynamic Switching Characteristics ...
... The Power Bipolar Junction Transistor (Part 3) Dynamic Switching Characteristics ...
Lecture Notes Chapter 19
... If it cost 10¢ per joule, how much did it cost? 100 J @ 0.1 = $10 OR Energy Cost = PΔt express in kW/h TLS: Problems 23-31 textbook, pp 603-605 ...
... If it cost 10¢ per joule, how much did it cost? 100 J @ 0.1 = $10 OR Energy Cost = PΔt express in kW/h TLS: Problems 23-31 textbook, pp 603-605 ...
Data Sheet Single Input Dual Output Isolating Amplifier
... Current: 0.5 * Rext max. Voltage: 2 * Rext min. Influence factors Temperature ± 0.15% per 10 °C Burden in uence < ± 0.1 % for current output < ± 0.1 % for voltage output Switch-on drift ...
... Current: 0.5 * Rext max. Voltage: 2 * Rext min. Influence factors Temperature ± 0.15% per 10 °C Burden in uence < ± 0.1 % for current output < ± 0.1 % for voltage output Switch-on drift ...
Evaluates: MAX1676 MAX1676 Evaluation Kit General Description Features
... The MAX1676 is a high-efficiency, step-up DC-DC converter for portable hand-held devices. It accepts a positive input voltage between 0.7V to 5.5V and converts it to a higher output voltage. The MAX1676 includes a damping circuit (at BATT) that suppresses inductor ringing to reduce electromagnetic i ...
... The MAX1676 is a high-efficiency, step-up DC-DC converter for portable hand-held devices. It accepts a positive input voltage between 0.7V to 5.5V and converts it to a higher output voltage. The MAX1676 includes a damping circuit (at BATT) that suppresses inductor ringing to reduce electromagnetic i ...
Exam 2 Solutions
... The parallel combination yields a resistance of 4 Ω and thus the total resistance is 6.0 Ω. The total current is thus 24 / 6.0 = 4 A. To find the current in the 6 Ω branch, first find the voltage across it, which is the same as the voltage across the parallel combination. This voltage is determined ...
... The parallel combination yields a resistance of 4 Ω and thus the total resistance is 6.0 Ω. The total current is thus 24 / 6.0 = 4 A. To find the current in the 6 Ω branch, first find the voltage across it, which is the same as the voltage across the parallel combination. This voltage is determined ...
2SD2142K
... VCE/IC=5V/10mA VCE/IC=5V/100mA IC/IB=100mA/0.1mA VCE/IC=5V/100mA VCE=5V , IE=−10mA , f=100MHz VCB=10V , IE=0A , f=1MHz ...
... VCE/IC=5V/10mA VCE/IC=5V/100mA IC/IB=100mA/0.1mA VCE/IC=5V/100mA VCE=5V , IE=−10mA , f=100MHz VCB=10V , IE=0A , f=1MHz ...
Current source
A current source is an electronic circuit that delivers or absorbs an electric current which is independent of the voltage across it.A current source is the dual of a voltage source. The term constant-current 'sink' is sometimes used for sources fed from a negative voltage supply. Figure 1 shows the schematic symbol for an ideal current source, driving a resistor load. There are two types - an independent current source (or sink) delivers a constant current. A dependent current source delivers a current which is proportional to some other voltage or current in the circuit.