B+ Tree
... Start at root, find leaf L where entry belongs. Remove the entry. › If L is at least half-full, done! › If L has only d-1 entries, Try to re-distribute, borrowing from sibling (adjacent node with same parent as L). If re-distribution fails, merge L and sibling. ...
... Start at root, find leaf L where entry belongs. Remove the entry. › If L is at least half-full, done! › If L has only d-1 entries, Try to re-distribute, borrowing from sibling (adjacent node with same parent as L). If re-distribution fails, merge L and sibling. ...
Data Structures in Java
... nodes such that the next node in the sequence is a child of the previous ...
... nodes such that the next node in the sequence is a child of the previous ...
1 Balanced Binary Search Trees
... Exercise. Find the best c you can which satisfies the above inequalities. ...
... Exercise. Find the best c you can which satisfies the above inequalities. ...
CSE 114 – Computer Science I Lecture 1
... – A binary tree has a left subtree & right subtree • Depth of a node – starting at a node, the number of steps up to reach the root • Depth of a tree – the maximum depth of any of its leaves ...
... – A binary tree has a left subtree & right subtree • Depth of a node – starting at a node, the number of steps up to reach the root • Depth of a tree – the maximum depth of any of its leaves ...
FinalExamReviewS07
... • You should be able to show how these algorithms perform on a given red-black tree (except for delete), and tell their running time ...
... • You should be able to show how these algorithms perform on a given red-black tree (except for delete), and tell their running time ...
Document
... Stacks – Linear structures Linear structure – Last In First Out (LIFO) Relative order of elements is maintained Can be built on a list or array. All operations are constant-time E.g.: The “undo” stack in an editor The operands and operators in a scientific ...
... Stacks – Linear structures Linear structure – Last In First Out (LIFO) Relative order of elements is maintained Can be built on a list or array. All operations are constant-time E.g.: The “undo” stack in an editor The operands and operators in a scientific ...
Chapter 10
... There are 3 ways to traverse a tree, that is, to visit every node: Preorder traversal: visit the current node, then traverse its left subtree, then its right subtree Postorder traversal: traverse the left subtree, then the right subtree, then visit the current node Inorder traversal: travers ...
... There are 3 ways to traverse a tree, that is, to visit every node: Preorder traversal: visit the current node, then traverse its left subtree, then its right subtree Postorder traversal: traverse the left subtree, then the right subtree, then visit the current node Inorder traversal: travers ...
Slides 3 - USC Upstate: Faculty
... Disadvantages of BST The shape of the tree depends on the order of insertions, and it can be degenerated. When inserting or searching for an element, the key of each visited node has to be compared with the key of the element to be inserted/found. Keys may be long and the run time may increase ...
... Disadvantages of BST The shape of the tree depends on the order of insertions, and it can be degenerated. When inserting or searching for an element, the key of each visited node has to be compared with the key of the element to be inserted/found. Keys may be long and the run time may increase ...
1 (i) - the David R. Cheriton School of Computer Science
... In a cycle there is a B every t positions … But these positions can be in arbitrary order Which i’s have a B, and how do we store it? Keep a vector of all positions 0 indicates no B 1 indicates a B Rank gives the position of B[“i”] in actual B array So: π(i) and π -1(i) in O(1) time & (1+ε)n lg n bi ...
... In a cycle there is a B every t positions … But these positions can be in arbitrary order Which i’s have a B, and how do we store it? Keep a vector of all positions 0 indicates no B 1 indicates a B Rank gives the position of B[“i”] in actual B array So: π(i) and π -1(i) in O(1) time & (1+ε)n lg n bi ...
Trees
... For trees, several well-defined visiting orders exist: Depth first traversals preorder (NLR) ... visit root, then left subtree, then right subtree inorder (LNR) ... visit left subtree, then root, then right subtree postorder (LRN) ... visit left subtree, then right subtree, then root Bread ...
... For trees, several well-defined visiting orders exist: Depth first traversals preorder (NLR) ... visit root, then left subtree, then right subtree inorder (LNR) ... visit left subtree, then root, then right subtree postorder (LRN) ... visit left subtree, then right subtree, then root Bread ...
Data structure
... In Binary trees All nodes contain two links None, one, or both of which may be NULL The root node is the first node in a tree. Each link in the root node refers to a child A node with no children is called a leaf node ...
... In Binary trees All nodes contain two links None, one, or both of which may be NULL The root node is the first node in a tree. Each link in the root node refers to a child A node with no children is called a leaf node ...