
Solution - Stony Brook Mathematics
... than x (since x/2 < x by the multiplicative law for inequalities), a contradiction. Therefore, there does not exist a smallest positive real number. Problem 4. Use induction to prove Bernouilli’s inequality : (1 + x)n ≥ 1 + nx for all non-negative integers n and real numbers x > −1. Sol. Fix some re ...
... than x (since x/2 < x by the multiplicative law for inequalities), a contradiction. Therefore, there does not exist a smallest positive real number. Problem 4. Use induction to prove Bernouilli’s inequality : (1 + x)n ≥ 1 + nx for all non-negative integers n and real numbers x > −1. Sol. Fix some re ...
Chapter 1 – ALGEBRA REVIEW
... 4.6 Factor a polynomial using only linear factors. 4.6 Determine the equation of a polynomial given its zeros or graph. 5.1 Define and apply rational exponents. 5.1 Simplify expressions containing radicals or rational exponents. 5.2 Graph and identify transformations of exponential functions. 5.3 U ...
... 4.6 Factor a polynomial using only linear factors. 4.6 Determine the equation of a polynomial given its zeros or graph. 5.1 Define and apply rational exponents. 5.1 Simplify expressions containing radicals or rational exponents. 5.2 Graph and identify transformations of exponential functions. 5.3 U ...
2 is irreducible in Q[ √ 2]
... to 7 so it cannot be isomorphic to Q[ 7]. • Exercises 4.1: 9, 14(a)(c). I went over these ones or very similar ones in class so I’m not going to do them here. • Exercises 3.3: 2(a)(c)(e), 4(a). 2(a) Is x3 + 4x2 − 3x + 5 irreducible in Q[x]? Its irreducible if and only if it has no rational roots whi ...
... to 7 so it cannot be isomorphic to Q[ 7]. • Exercises 4.1: 9, 14(a)(c). I went over these ones or very similar ones in class so I’m not going to do them here. • Exercises 3.3: 2(a)(c)(e), 4(a). 2(a) Is x3 + 4x2 − 3x + 5 irreducible in Q[x]? Its irreducible if and only if it has no rational roots whi ...