Title BP operations and homological properties of
... Let / be an invariant regular ideal in BP* of finite length. There is a left 2?P-module spectrum BPJ whose homotopy is BP*/J. When J is trivial, BPJ is just BP. we do prove our results for (associative) .BP/*i?P/-comodules. A reader who is interested only in associative l?P#i?P-comodules may neglect ...
... Let / be an invariant regular ideal in BP* of finite length. There is a left 2?P-module spectrum BPJ whose homotopy is BP*/J. When J is trivial, BPJ is just BP. we do prove our results for (associative) .BP/*i?P/-comodules. A reader who is interested only in associative l?P#i?P-comodules may neglect ...
(A B) (A B) (A B) (A B)
... real numbers to the set of real numbers. We say that f(x) is O(g(x)) if there are constants CN and kR such that |f(x)| C|g(x)| whenever x > k. • We say “f(x) is big-oh of g(x)”. • The intuitive meaning is that as x gets large, the values of f(x) are no larger than a constant time the values of g ...
... real numbers to the set of real numbers. We say that f(x) is O(g(x)) if there are constants CN and kR such that |f(x)| C|g(x)| whenever x > k. • We say “f(x) is big-oh of g(x)”. • The intuitive meaning is that as x gets large, the values of f(x) are no larger than a constant time the values of g ...
On mathematical induction
... Proof. We prove the theorem by induction over n. First we check the case in which A contains 0 elements. In this case A is the empty set ∅ and his only subset is the empty set itself. In other word P(A) = {∅} contains only one element and, since 20 = 1 this implies that the theorem is true for n = 0 ...
... Proof. We prove the theorem by induction over n. First we check the case in which A contains 0 elements. In this case A is the empty set ∅ and his only subset is the empty set itself. In other word P(A) = {∅} contains only one element and, since 20 = 1 this implies that the theorem is true for n = 0 ...
04 commutative rings I
... Let’s check that J is an ideal. First 0=0·x+0 so 0 lies in J. Second, −(rx + i) = (−r)x + (−i) so J is closed under inverses. Third, for two elements rx + i and r0 x + i0 in J (with r, r0 ∈ R and i, i0 ∈ I) we have (rx + i) + (r0 x + i0 ) = (r + r0 )x + (i + i0 ) so J is closed under addition. Final ...
... Let’s check that J is an ideal. First 0=0·x+0 so 0 lies in J. Second, −(rx + i) = (−r)x + (−i) so J is closed under inverses. Third, for two elements rx + i and r0 x + i0 in J (with r, r0 ∈ R and i, i0 ∈ I) we have (rx + i) + (r0 x + i0 ) = (r + r0 )x + (i + i0 ) so J is closed under addition. Final ...
THEOREM 1.1. Let G be a finite sovable group. Let two subgroups U
... In [2], it was shown that Losey-Stonehewer theorm holds without solvability. It is desired to generalize the theorem for infinite groups. In fact we have some generalizations for specific classes of locally finite groups[7]. In this note, we are concerned with profinite groups. 2. Profinite group An ...
... In [2], it was shown that Losey-Stonehewer theorm holds without solvability. It is desired to generalize the theorem for infinite groups. In fact we have some generalizations for specific classes of locally finite groups[7]. In this note, we are concerned with profinite groups. 2. Profinite group An ...
