Solutions to problem sheet 1.
... n is odd. But the square of any odd number is also odd (Liebeck, Example 1.2). Hence n2 is odd, which is a contradiction. c. n = m3 − m = m(m2 − 1) = m(m − 1)(m + 1). Hence n is the product of three successive integers. But any three successive integers contains both an even number and a multiple of ...
... n is odd. But the square of any odd number is also odd (Liebeck, Example 1.2). Hence n2 is odd, which is a contradiction. c. n = m3 − m = m(m2 − 1) = m(m − 1)(m + 1). Hence n is the product of three successive integers. But any three successive integers contains both an even number and a multiple of ...
Graphing Square Root Functions
... Since a radicand can’t be negative (you can’t square a negative value), the domain (x values) is limited to those values of x that make the radicand greater than or equal to zero. Therefore, you can create a function table to graph the solutions with x being values that make the expression inside th ...
... Since a radicand can’t be negative (you can’t square a negative value), the domain (x values) is limited to those values of x that make the radicand greater than or equal to zero. Therefore, you can create a function table to graph the solutions with x being values that make the expression inside th ...
