Discrete Math
... Discrete Math: Assignment I January 9, 2007 1. Find the error in the following inductive proof showing that all the integers in any set of integers are equal: Base Case: Trivial! Inductive Step: Suppose all sets of size n − 1 have all elements equal. Now given a set S of size n consider the two sets ...
... Discrete Math: Assignment I January 9, 2007 1. Find the error in the following inductive proof showing that all the integers in any set of integers are equal: Base Case: Trivial! Inductive Step: Suppose all sets of size n − 1 have all elements equal. Now given a set S of size n consider the two sets ...
Lesson 1.1
... The Milky Way has a diameter of 6 x 1017 miles. If the speed of light is 186,000 miles/sec, how many years does it take for light to travel across the galaxy? ...
... The Milky Way has a diameter of 6 x 1017 miles. If the speed of light is 186,000 miles/sec, how many years does it take for light to travel across the galaxy? ...
![[Part 2]](http://s1.studyres.com/store/data/008795852_1-cad52ff07db278d6ae8b566caa06ee72-300x300.png)
[Part 2]
... Sn studying the sequences (3,4), non-periodic sequences of a quasi-periodic type were found. They have the peculiar property that alternate terms form a regular pattern in groups of four, while the intermediate terms between these pattern terms become unbounded. This situation arises in sequences (p ...
... Sn studying the sequences (3,4), non-periodic sequences of a quasi-periodic type were found. They have the peculiar property that alternate terms form a regular pattern in groups of four, while the intermediate terms between these pattern terms become unbounded. This situation arises in sequences (p ...
jeopardy for symbols and sets of numbers
... Less than or equal to Look like? Draw it on the board. ...
... Less than or equal to Look like? Draw it on the board. ...
PDF
... Since f (z) has no zeros outside the polygon, we have, according to (2), to show only that the same concerns the second factor of the right hand side of (2). Let z be an arbitrary point outside the polygon. Because of its convexity, there is a line l through z such that the polygon is completely on ...
... Since f (z) has no zeros outside the polygon, we have, according to (2), to show only that the same concerns the second factor of the right hand side of (2). Let z be an arbitrary point outside the polygon. Because of its convexity, there is a line l through z such that the polygon is completely on ...
