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... L. Bastien and others have stated that a prime of form (Sr + 1) , representable as (k + t ) cannot be congruent if (k + t) is not a quadratic residue of that prime. But no proof of this has been known to exist in the literature. The necessary proof will be developed in this paper. We first show that ...
... L. Bastien and others have stated that a prime of form (Sr + 1) , representable as (k + t ) cannot be congruent if (k + t) is not a quadratic residue of that prime. But no proof of this has been known to exist in the literature. The necessary proof will be developed in this paper. We first show that ...
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... For a positive integer n, let f(ri) be the number of multiplicative partitions of n. That is, f(n) represents the number of different factorizations of n, where two factorizations are considered the same if they differ only in the order of the factors. For example, /"(12) = 4, since 12 = 6*2 = 4 • 3 ...
... For a positive integer n, let f(ri) be the number of multiplicative partitions of n. That is, f(n) represents the number of different factorizations of n, where two factorizations are considered the same if they differ only in the order of the factors. For example, /"(12) = 4, since 12 = 6*2 = 4 • 3 ...
Math 9: 2.3 Problem Solving with Rational Numbers in Fraction Form
... a) Explain why she had difficulty in determining the exact answer by this method. b) How should she calculate to get an exact answer? ...
... a) Explain why she had difficulty in determining the exact answer by this method. b) How should she calculate to get an exact answer? ...
A Pisot number (or P.V. number) is an algebraic integer greater than
... hence 1 is a zero of Q. In [5], we showed that each of Q0 and Q00 has exactly one zero outside D and those two zeros must be real numbers greater than 1. So, if we could find a positive uniform lower bound for β − 1, where β runs over all zeros of Q0 greater than 1, then this would assure that T has ...
... hence 1 is a zero of Q. In [5], we showed that each of Q0 and Q00 has exactly one zero outside D and those two zeros must be real numbers greater than 1. So, if we could find a positive uniform lower bound for β − 1, where β runs over all zeros of Q0 greater than 1, then this would assure that T has ...
