A New Connection Between the Triangles of Stirling and Pascal
... white triangle began with 1 and this isn’t a perfect number! That’s true, Pascal’s triangle doesn’t always yield perfect numbers in this manner, but every even perfect number does appear somewhere in this sequence. This is because the number of elements in each white triangle is given by 2n –1(2n – ...
... white triangle began with 1 and this isn’t a perfect number! That’s true, Pascal’s triangle doesn’t always yield perfect numbers in this manner, but every even perfect number does appear somewhere in this sequence. This is because the number of elements in each white triangle is given by 2n –1(2n – ...
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... It is well known that the sum of any ten numbers of a Fibonacci sequence is divisible by 11. For example, starting with 11, 15 and proceeding to 26,41, 67, 108, 175, 283, 458, 741, the sum of these ten terms is 1925 which is divisible by 11, the quotient being 175, the seventh member of the set of t ...
... It is well known that the sum of any ten numbers of a Fibonacci sequence is divisible by 11. For example, starting with 11, 15 and proceeding to 26,41, 67, 108, 175, 283, 458, 741, the sum of these ten terms is 1925 which is divisible by 11, the quotient being 175, the seventh member of the set of t ...
CS300-07
... MM : Given a set of n real numbers, find max and min. max = the largest number min = the smallest number How can you solve MM? x1 x2 x3 x4 …… x2n-1 x2m W {x11, x21, x31,……, xm1} max L {x12, x22, x32,……, xm2} min How many comparisons? m ...
... MM : Given a set of n real numbers, find max and min. max = the largest number min = the smallest number How can you solve MM? x1 x2 x3 x4 …… x2n-1 x2m W {x11, x21, x31,……, xm1} max L {x12, x22, x32,……, xm2} min How many comparisons? m ...
Generalization of the Genocchi Numbers to their q-analogue Matthew Rogala April 15, 2008
... To verify that this generalized formula does indeed result in the classical hypergeometric series when the limit as q approaches 1 is taken, we simply take that limit upon the general term of the series. So, we’re looking at (q α ; q)n (q β ; q)n q→1 (q; q)n (q γ ; q)n ...
... To verify that this generalized formula does indeed result in the classical hypergeometric series when the limit as q approaches 1 is taken, we simply take that limit upon the general term of the series. So, we’re looking at (q α ; q)n (q β ; q)n q→1 (q; q)n (q γ ; q)n ...
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... BOOK REVIEW Richard A. Dunlap, The Golden Ratio and Fibonacci Numbers (River Edge, NJ: World Scientific, 1997). This attractive and carefully written book addresses the general reader with interest in mathematics and its application to the physical and biological sciences. In addition, it provides s ...
... BOOK REVIEW Richard A. Dunlap, The Golden Ratio and Fibonacci Numbers (River Edge, NJ: World Scientific, 1997). This attractive and carefully written book addresses the general reader with interest in mathematics and its application to the physical and biological sciences. In addition, it provides s ...
