11.13.14 geometric
... In a geometric sequence, the ratio of any term to the previous term is constant. You keep multiplying by the SAME number each time to get the sequence. ...
... In a geometric sequence, the ratio of any term to the previous term is constant. You keep multiplying by the SAME number each time to get the sequence. ...
Real Exponents
... (since 2x is an increasing function for rational x). Also, since 2 < 2, the sequence of approximations are all less than 22 = 4. A basic ...
... (since 2x is an increasing function for rational x). Also, since 2 < 2, the sequence of approximations are all less than 22 = 4. A basic ...
On Determining the Irrationality of the Mean of a Random Variable.
... Second, although 12, - pl --t 0, any confidence interval centered at Zn contains an infinite number of rational and irrational parameters p which are likely causes for x,, xZ, ., x,. We shall return to the coin flipping problem after we have exhibited a proof of a somewhat more general result. Let x ...
... Second, although 12, - pl --t 0, any confidence interval centered at Zn contains an infinite number of rational and irrational parameters p which are likely causes for x,, xZ, ., x,. We shall return to the coin flipping problem after we have exhibited a proof of a somewhat more general result. Let x ...
Math Awareness Month Competition 2010 Solutions for 5th
... [Solution: Among the given distances, the largest one equals the sum of all the others: 8 = 2 + 1.5 + 3.5 + 1. This is possible only if the sheds are along a line. The order of the sheds must be C, B, A, E, D. Therefore, distant(B, E) = distant(B, A) + distant(A, E) = 2 + 1 = 3 miles.] 4. We write t ...
... [Solution: Among the given distances, the largest one equals the sum of all the others: 8 = 2 + 1.5 + 3.5 + 1. This is possible only if the sheds are along a line. The order of the sheds must be C, B, A, E, D. Therefore, distant(B, E) = distant(B, A) + distant(A, E) = 2 + 1 = 3 miles.] 4. We write t ...
