Chapter 6 – Solving equations Defining an equation 6.1 Up to now
... i.e. x(x+4) = 0 So x = 0 and x = -4. Solve: 4x - x2 = 0 4x - x2 = 0 x(4 – x) = 0 It is now a ZPE. x = 0 and x = 4. Now consider the quadratic equation: x2 + 4x = -3. Note the RHS is not zero. To make this into a ZPE we first make the RHS = 0 by moving the term, -3 from the LHS to the RHS viz: x2 + ...
... i.e. x(x+4) = 0 So x = 0 and x = -4. Solve: 4x - x2 = 0 4x - x2 = 0 x(4 – x) = 0 It is now a ZPE. x = 0 and x = 4. Now consider the quadratic equation: x2 + 4x = -3. Note the RHS is not zero. To make this into a ZPE we first make the RHS = 0 by moving the term, -3 from the LHS to the RHS viz: x2 + ...
