
Chapter 9
... The linear momentum of a particle or an object that can be modeled as a particle of mass m moving with a velocity v is defined to be the product of the mass and velocity: ...
... The linear momentum of a particle or an object that can be modeled as a particle of mass m moving with a velocity v is defined to be the product of the mass and velocity: ...
2004_11_03ImpulseMomentum
... Chapter 7 Impulse and Momentum Impulse and momentum play important roles in sports. ...
... Chapter 7 Impulse and Momentum Impulse and momentum play important roles in sports. ...
Object Orientation and Rotation
... in the direction of a. Using this Ixy, Ixz and Iyz can be calculated, e.g. Ixy holds the sum of the products of mass dependent upon the distance of the particle along the x- and y-axis relative to the centre of mass. A product of inertia represents the tendency to rotate in a direction different fro ...
... in the direction of a. Using this Ixy, Ixz and Iyz can be calculated, e.g. Ixy holds the sum of the products of mass dependent upon the distance of the particle along the x- and y-axis relative to the centre of mass. A product of inertia represents the tendency to rotate in a direction different fro ...
Remember EVERY ANSWER needs a number unit and direction
... the terms have i,j,k components. This equations says the velocity of point B is equal to the velocity of point A (Translation) + the angular velocity crossed with the position vector of b with respect to a (Rotation about a Fixed Axis). The subscripts are important. With respect to A means you start ...
... the terms have i,j,k components. This equations says the velocity of point B is equal to the velocity of point A (Translation) + the angular velocity crossed with the position vector of b with respect to a (Rotation about a Fixed Axis). The subscripts are important. With respect to A means you start ...
real world examples.
... Newton’s Laws 1 & 2 for 300 An object accelerates at 4 meters per second2 for a force of 20 N. How much force is needed for an acceleration of 40 m/s/s for the same object? If the amount of force on a heavy object is the same as the amount of force on a lighter object, then which object will have t ...
... Newton’s Laws 1 & 2 for 300 An object accelerates at 4 meters per second2 for a force of 20 N. How much force is needed for an acceleration of 40 m/s/s for the same object? If the amount of force on a heavy object is the same as the amount of force on a lighter object, then which object will have t ...
Phys 111 CE1 2013 Fall
... First, write your name and section number on both the Scantron card and this exam sheet. Use the formula sheet (last exam booklet page) and no other materials. Budget your time. There are 18 multiple choice problems. For most, if not all, of the multiple choice problems, it will be difficult to arri ...
... First, write your name and section number on both the Scantron card and this exam sheet. Use the formula sheet (last exam booklet page) and no other materials. Budget your time. There are 18 multiple choice problems. For most, if not all, of the multiple choice problems, it will be difficult to arri ...
Theoretical questions
... 1. Define the position vector of the mass point. Explain the conception of position vector differential in the appropriate figure. Describe its properties (magnitude, direction). 2. Define velocity of the mass point. Describe its properties. Define the acceleration of the mass point. Express its vel ...
... 1. Define the position vector of the mass point. Explain the conception of position vector differential in the appropriate figure. Describe its properties (magnitude, direction). 2. Define velocity of the mass point. Describe its properties. Define the acceleration of the mass point. Express its vel ...
SPH4U: Lecture 14 Notes
... The concept of momentum conservation is one of the most fundamental principles in physics. This is a component (vector) equation. We can apply it to any direction in which there is no external force applied. You will see that we often have momentum conservation (FEXT=0) even when mechanical energy ...
... The concept of momentum conservation is one of the most fundamental principles in physics. This is a component (vector) equation. We can apply it to any direction in which there is no external force applied. You will see that we often have momentum conservation (FEXT=0) even when mechanical energy ...
Forces - Images
... • Newton found 3 laws of motion that are true throughout the universe. • Newton’s First Law of Motion: – Objects at rest will remain at rest, and objects in motion will remain in motion, unless an unbalanced force acts on them. ...
... • Newton found 3 laws of motion that are true throughout the universe. • Newton’s First Law of Motion: – Objects at rest will remain at rest, and objects in motion will remain in motion, unless an unbalanced force acts on them. ...
AP Physics C ID
... collides with a 500 kg traveling due west at 30.0 m/s. The cars lock bumpers and stick together. What is the velocity of the combined cars immediately after impact? ...
... collides with a 500 kg traveling due west at 30.0 m/s. The cars lock bumpers and stick together. What is the velocity of the combined cars immediately after impact? ...
Relativistic angular momentum
""Angular momentum tensor"" redirects to here.In physics, relativistic angular momentum refers to the mathematical formalisms and physical concepts that define angular momentum in special relativity (SR) and general relativity (GR). The relativistic quantity is subtly different from the three-dimensional quantity in classical mechanics.Angular momentum is a dynamical quantity derived from position and momentum, and is important; angular momentum is a measure of an object's ""amount of rotational motion"" and resistance to stop rotating. Also, in the same way momentum conservation corresponds to translational symmetry, angular momentum conservation corresponds to rotational symmetry – the connection between symmetries and conservation laws is made by Noether's theorem. While these concepts were originally discovered in classical mechanics – they are also true and significant in special and general relativity. In terms of abstract algebra; the invariance of angular momentum, four-momentum, and other symmetries in spacetime, are described by the Poincaré group and Lorentz group.Physical quantities which remain separate in classical physics are naturally combined in SR and GR by enforcing the postulates of relativity, an appealing characteristic. Most notably; space and time coordinates combine into the four-position, and energy and momentum combine into the four-momentum. These four-vectors depend on the frame of reference used, and change under Lorentz transformations to other inertial frames or accelerated frames.Relativistic angular momentum is less obvious. The classical definition of angular momentum is the cross product of position x with momentum p to obtain a pseudovector x×p, or alternatively as the exterior product to obtain a second order antisymmetric tensor x∧p. What does this combine with, if anything? There is another vector quantity not often discussed – it is the time-varying moment of mass (not the moment of inertia) related to the boost of the centre of mass of the system, and this combines with the classical angular momentum to form an antisymmetric tensor of second order. For rotating mass–energy distributions (such as gyroscopes, planets, stars, and black holes) instead of point-like particles, the angular momentum tensor is expressed in terms of the stress–energy tensor of the rotating object.In special relativity alone, in the rest frame of a spinning object; there is an intrinsic angular momentum analogous to the ""spin"" in quantum mechanics and relativistic quantum mechanics, although for an extended body rather than a point particle. In relativistic quantum mechanics, elementary particles have spin and this is an additional contribution to the orbital angular momentum operator, yielding the total angular momentum tensor operator. In any case, the intrinsic ""spin"" addition to the orbital angular momentum of an object can be expressed in terms of the Pauli–Lubanski pseudovector.