Force and weight
... What is this weight in newtons? What is this person’s mass in kilograms? A 10 kg dumbbell resting on a table is partly supported by a spring that pulls upward with a force of 50 N. ...
... What is this weight in newtons? What is this person’s mass in kilograms? A 10 kg dumbbell resting on a table is partly supported by a spring that pulls upward with a force of 50 N. ...
Centripetal Force
... In this experiment we will measure the force required to keep a mass moving at constant angular velocity in a circle of constant radius. This force will be applied by a spring suspended between the mass and a post at the center of the circle about which the mass rotates. The general outline of the a ...
... In this experiment we will measure the force required to keep a mass moving at constant angular velocity in a circle of constant radius. This force will be applied by a spring suspended between the mass and a post at the center of the circle about which the mass rotates. The general outline of the a ...
Galaxy Structure
... smaller group of three large and over 30 small galaxies, and is the second largest (after the Andromeda Galaxy M31) but perhaps the most massive member of this group. The Milky Way is most likely a BARRED SPIRAL GALAXY of Hubble type SBc. We are situated within the outer regions of its spiral disk, ...
... smaller group of three large and over 30 small galaxies, and is the second largest (after the Andromeda Galaxy M31) but perhaps the most massive member of this group. The Milky Way is most likely a BARRED SPIRAL GALAXY of Hubble type SBc. We are situated within the outer regions of its spiral disk, ...
ch 13 - Simple Harmonic Motion
... kg, and the oscillating mass released from rest at x = 0.020 m. a. Find the maximum and minimum velocities attained by the oscillating body. b. Compute the maximum acceleration. c. Determine the velocity and acceleration when the body has moved halfway to the center from its original position. d. Fi ...
... kg, and the oscillating mass released from rest at x = 0.020 m. a. Find the maximum and minimum velocities attained by the oscillating body. b. Compute the maximum acceleration. c. Determine the velocity and acceleration when the body has moved halfway to the center from its original position. d. Fi ...
Cannot reproduce observed Log N – Log S
... The closest millisecond PSR. MNS=1.76+/-0.2 solar. Hopefully, this value will not be reconsidered. 2. The case of PSR J0751+1807. Initially, it was announced that it has a mass ~2.1 solar [astro-ph/0508050]. However, then in 2007 at a conference the authors announced that the result was incorrect. A ...
... The closest millisecond PSR. MNS=1.76+/-0.2 solar. Hopefully, this value will not be reconsidered. 2. The case of PSR J0751+1807. Initially, it was announced that it has a mass ~2.1 solar [astro-ph/0508050]. However, then in 2007 at a conference the authors announced that the result was incorrect. A ...
Lecture Topics 1023
... ASTR 1023 Lecture Topics These are the headings of the paragraphs into which ASTR 1023 lectures are divided. Use them to check your notes for completeness, and to see how the course is organized. It is also a good idea to cross-check these topics with your reading assignments, because some topics ar ...
... ASTR 1023 Lecture Topics These are the headings of the paragraphs into which ASTR 1023 lectures are divided. Use them to check your notes for completeness, and to see how the course is organized. It is also a good idea to cross-check these topics with your reading assignments, because some topics ar ...
File - SPH3U- 11 University Prep Physics
... ____ 12. Which of the fundamental forces is directly responsible for frictional forces? a. strong nuclear force d. electromagnetic force b. weak nuclear force e. a combination of all forces c. gravitational force ____ 13. The coefficient of friction stems from the a. nature of the two surfaces in co ...
... ____ 12. Which of the fundamental forces is directly responsible for frictional forces? a. strong nuclear force d. electromagnetic force b. weak nuclear force e. a combination of all forces c. gravitational force ____ 13. The coefficient of friction stems from the a. nature of the two surfaces in co ...
X-ray binaries
... LMXBs with NSs or BHs The latest large catalogue (Li et al. arXiv: 0707.0544) includes 187 galactic and Magellanic Clouds LMXBs with NSs and BHs as accreting components. Donors can be WDs, or normal low-mass stars (main sequence or sub-giants). Many sources are found in globular clusters. Also ther ...
... LMXBs with NSs or BHs The latest large catalogue (Li et al. arXiv: 0707.0544) includes 187 galactic and Magellanic Clouds LMXBs with NSs and BHs as accreting components. Donors can be WDs, or normal low-mass stars (main sequence or sub-giants). Many sources are found in globular clusters. Also ther ...
Static Equilibrium
... To be in static equilibrium, a rigid body must also be in rotational static equilibrium. Although the sum of the forces on the body may be zero and it is not moving linearly, it is possible that it may be rotating about some fixed axis of rotation. However, if the sum of the torques is zero, ∑τ = 0 ...
... To be in static equilibrium, a rigid body must also be in rotational static equilibrium. Although the sum of the forces on the body may be zero and it is not moving linearly, it is possible that it may be rotating about some fixed axis of rotation. However, if the sum of the torques is zero, ∑τ = 0 ...
Lecture slides with notes
... I’m going to try something that I think will help you guys learn: since we’ve already covered conservation of energy, I want you you to try to puzzle through the application of this concept to rotational motion yourself, to help you build intuition for these equations and how to use them. To do that ...
... I’m going to try something that I think will help you guys learn: since we’ve already covered conservation of energy, I want you you to try to puzzle through the application of this concept to rotational motion yourself, to help you build intuition for these equations and how to use them. To do that ...
Rotational motion and torque notes
... Rotational Equilibrium An object is in rotational equilibirum (its angular momentum is constant) if the sum of the torques acting on it is zero. An object will be in equilibrium if it is suspended from its center of gravity or its center of gravity is below the suspension point. Elasticity The branc ...
... Rotational Equilibrium An object is in rotational equilibirum (its angular momentum is constant) if the sum of the torques acting on it is zero. An object will be in equilibrium if it is suspended from its center of gravity or its center of gravity is below the suspension point. Elasticity The branc ...
Characteristics of Force
... say, so the most precise and beautiful definition of force imaginable might simply be to say that force is the mass of an object times the acceleration. Suppose we have a law which says that the conservation of momentum is valid if the sum of all the external forces is zero; then the question arises ...
... say, so the most precise and beautiful definition of force imaginable might simply be to say that force is the mass of an object times the acceleration. Suppose we have a law which says that the conservation of momentum is valid if the sum of all the external forces is zero; then the question arises ...
2nd 9 weeks
... I can explain that, when friction is present in a system, the mechanical energy decreases but the total energy remains constant. I can calculate the velocity of an object free falling from a given height using conservation of mechanical energy. I can calculate the maximum height of an object given a ...
... I can explain that, when friction is present in a system, the mechanical energy decreases but the total energy remains constant. I can calculate the velocity of an object free falling from a given height using conservation of mechanical energy. I can calculate the maximum height of an object given a ...
Feedback - Cambridge University Press
... Recent observations constrain both the abundance of dark matter galaxy halos and the luminosity function of galaxies with a fair amount of precision. The result shows that star formation efficiency, defined as the ratio of stellar mass to halo mass, has a fairly sharp peak at a halo mass slightly below ...
... Recent observations constrain both the abundance of dark matter galaxy halos and the luminosity function of galaxies with a fair amount of precision. The result shows that star formation efficiency, defined as the ratio of stellar mass to halo mass, has a fairly sharp peak at a halo mass slightly below ...
The False Force - Gravity
... contrary to the common belief and principle. Einstein too challenged the basics of gravity in his theory of General Relativity. Einstein believed that gravity may be caused due to the curvature of space time. While this is a step in the right direction, Einstein’s idea is also objectionable. The cur ...
... contrary to the common belief and principle. Einstein too challenged the basics of gravity in his theory of General Relativity. Einstein believed that gravity may be caused due to the curvature of space time. While this is a step in the right direction, Einstein’s idea is also objectionable. The cur ...
Wednesday, February 13, 2008
... body will be rigidly maintained as long as the external causes of retardation are removed!! Galileo’s statement is formulated by Newton into the 1st law of motion (Law of Inertia): In the absence of external forces, an object at rest remains at rest and ...
... body will be rigidly maintained as long as the external causes of retardation are removed!! Galileo’s statement is formulated by Newton into the 1st law of motion (Law of Inertia): In the absence of external forces, an object at rest remains at rest and ...
Modified Newtonian dynamics
In physics, modified Newtonian dynamics (MOND) is a theory that proposes a modification of Newton's laws to account for observed properties of galaxies. Created in 1983 by Israeli physicist Mordehai Milgrom, the theory's original motivation was to explain the fact that the velocities of stars in galaxies were observed to be larger than expected based on Newtonian mechanics. Milgrom noted that this discrepancy could be resolved if the gravitational force experienced by a star in the outer regions of a galaxy was proportional to the square of its centripetal acceleration (as opposed to the centripetal acceleration itself, as in Newton's Second Law), or alternatively if gravitational force came to vary inversely with radius (as opposed to the inverse square of the radius, as in Newton's Law of Gravity). In MOND, violation of Newton's Laws occurs at extremely small accelerations, characteristic of galaxies yet far below anything typically encountered in the Solar System or on Earth.MOND is an example of a class of theories known as modified gravity, and is an alternative to the hypothesis that the dynamics of galaxies are determined by massive, invisible dark matter halos. Since Milgrom's original proposal, MOND has successfully predicted a variety of galactic phenomena that are difficult to understand from a dark matter perspective. However, MOND and its generalisations do not adequately account for observed properties of galaxy clusters, and no satisfactory cosmological model has been constructed from the theory.