Powers of ten notation
									
... Earth raises tides on the Moon. But the tides are not raised in water but in the very crust of the Moon. The Earth’s gravity pulling on these tidal bulges slowed the Moon’s rotation period over millions to a period equal to that of the Moon’s orbit. ...
                        	... Earth raises tides on the Moon. But the tides are not raised in water but in the very crust of the Moon. The Earth’s gravity pulling on these tidal bulges slowed the Moon’s rotation period over millions to a period equal to that of the Moon’s orbit. ...
									File - SloanZone Physics
									
... 17. How much work must be done to lift a 4.00 x10 4 kg object from Earth’s surface to a height of 3.00 x105 m? A. 1.12 x1011 J B. 1.18 x1011 J C. 2.39 x1012 J D. 5.32 x1013 J 18. The equation Ep = mgh, in which g is 9.8 m/s2 , can not be used for calculating the gravitational potential energy of an ...
                        	... 17. How much work must be done to lift a 4.00 x10 4 kg object from Earth’s surface to a height of 3.00 x105 m? A. 1.12 x1011 J B. 1.18 x1011 J C. 2.39 x1012 J D. 5.32 x1013 J 18. The equation Ep = mgh, in which g is 9.8 m/s2 , can not be used for calculating the gravitational potential energy of an ...
									HW #5
									
... a. Calculate Bond’s velocity just before impact. b. Find the average acceleration [added later: and the average force on the torso due to the legs] during deceleration. (Hint: Draw that free-body diagram!) 3. A block on a smooth horizontal surface is connected by a thin rope passing over a pulley to ...
                        	... a. Calculate Bond’s velocity just before impact. b. Find the average acceleration [added later: and the average force on the torso due to the legs] during deceleration. (Hint: Draw that free-body diagram!) 3. A block on a smooth horizontal surface is connected by a thin rope passing over a pulley to ...
									Document
									
... applied to CM, so that its lever arm is zero and the torque vanishes. The object does not rotationally accelerate around ist own CM under the influence of gravitational force and it only can have linear (translational) acceleration. If we now choose another pivot point that does not coincide with CM ...
                        	... applied to CM, so that its lever arm is zero and the torque vanishes. The object does not rotationally accelerate around ist own CM under the influence of gravitational force and it only can have linear (translational) acceleration. If we now choose another pivot point that does not coincide with CM ...
									Document
									
... Michelangelo’s assistant has been assigned the task of moving a block of marble using a sled. He says to his boss, “When I exert a forward force on the sled, the sled exerts an equal and opposite force backward. So how can I ever start it moving? No matter how hard I pull, the backward reaction forc ...
                        	... Michelangelo’s assistant has been assigned the task of moving a block of marble using a sled. He says to his boss, “When I exert a forward force on the sled, the sled exerts an equal and opposite force backward. So how can I ever start it moving? No matter how hard I pull, the backward reaction forc ...
									- Review the Law of Interaction and balanced forces within bodies
									
... Also a pair of opposing forces between hands and the scale (not shown) ...
                        	... Also a pair of opposing forces between hands and the scale (not shown) ...
									Chapter 13 - AJRomanello
									
... FΔt = mΔV  In an angular system the change in angular momentum is given by: FrΔt = IΔω or ΤΔt = IΔω ...
                        	... FΔt = mΔV  In an angular system the change in angular momentum is given by: FrΔt = IΔω or ΤΔt = IΔω ...
									W3.13 Newton`s Law Quick Hitters 2
									
... 4. A 10-kilogram bucket is lowered by a rope in which there is 63 N of tension. What is the acceleration of the bucket? 5. The cable supporting a 2100-kilogram elevator has a maximum strength of 21, 750 N. What maximum upward acceleration can it give the elevator without breaking? 6. According to a ...
                        	... 4. A 10-kilogram bucket is lowered by a rope in which there is 63 N of tension. What is the acceleration of the bucket? 5. The cable supporting a 2100-kilogram elevator has a maximum strength of 21, 750 N. What maximum upward acceleration can it give the elevator without breaking? 6. According to a ...
									Forces in Motion
									
... object will continue to accelerate downward.  The amount of air resistance on an object increases as the speed of the object increases.  As an object falls, the upward force of air resistance continues to increase until it exactly matches the downward force of gravity.  When this happens, the net ...
                        	... object will continue to accelerate downward.  The amount of air resistance on an object increases as the speed of the object increases.  As an object falls, the upward force of air resistance continues to increase until it exactly matches the downward force of gravity.  When this happens, the net ...
									Jeopardy
									
... at rest and an object in motion tends to stay in motion unless acted upon by an external force”? ...
                        	... at rest and an object in motion tends to stay in motion unless acted upon by an external force”? ...
Newton's theorem of revolving orbits
In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.