Honors_Physics_-_Circular_Motion
... means “CENTER SEEKING”. So for an object traveling in a counter-clockwise path. The velocity would be drawn TANGENT to the circle and the acceleration would be drawn TOWARDS the CENTER. To find the MAGNITUDES of each we have: ...
... means “CENTER SEEKING”. So for an object traveling in a counter-clockwise path. The velocity would be drawn TANGENT to the circle and the acceleration would be drawn TOWARDS the CENTER. To find the MAGNITUDES of each we have: ...
wk13-ppt
... Jersey shore compared to its value if it is on top of Mt. Everest. B) The acceleration due to gravity g depends on where on the earths surface it is measured. C) The gravitational force of the earth on the moon depends on the velocity of the moon relative to the earth. D) The acceleration of an obje ...
... Jersey shore compared to its value if it is on top of Mt. Everest. B) The acceleration due to gravity g depends on where on the earths surface it is measured. C) The gravitational force of the earth on the moon depends on the velocity of the moon relative to the earth. D) The acceleration of an obje ...
MATH10222, Chapter 2: Newtonian Dynamics 1 Newton`s Laws 2
... Answer: Oscillatory motion is only possible if there are two points at which ẋ = 0, and in between these two points we must have E > V (x). This is only possible if a horizontal line at a value of E intersects V (x) twice either side of a minimum. From the sketch of the solution, this is only possi ...
... Answer: Oscillatory motion is only possible if there are two points at which ẋ = 0, and in between these two points we must have E > V (x). This is only possible if a horizontal line at a value of E intersects V (x) twice either side of a minimum. From the sketch of the solution, this is only possi ...
Force and Newtons Laws
... 1. If a car travels west 75 kilometers takes a uturn and travels back east 25 kilometers what is the car’s final displacement? 50 km west 2. If a car at rest, traveled north 5.5 s and reached a final velocity of 22.0 m/s, what was the car’s acceleration? 4.0 m/s2 ...
... 1. If a car travels west 75 kilometers takes a uturn and travels back east 25 kilometers what is the car’s final displacement? 50 km west 2. If a car at rest, traveled north 5.5 s and reached a final velocity of 22.0 m/s, what was the car’s acceleration? 4.0 m/s2 ...
NEWTON`S FIRST LAW OF MOTION The law of INERTIA
... How does a traveling object move once all the forces on it are balanced? at a constant speed in a straight line Why don’t things just move at a constant speed in a straight line forever then on Earth? FRICTION! Opposes the motion & slows things down or GRAVITY if motion is in up/down direction Thes ...
... How does a traveling object move once all the forces on it are balanced? at a constant speed in a straight line Why don’t things just move at a constant speed in a straight line forever then on Earth? FRICTION! Opposes the motion & slows things down or GRAVITY if motion is in up/down direction Thes ...
Torque Torque is defined as the measure of tendency of a force to
... At which point, A or B, would you push? Clearly that would be point A. Why? Because you know that you can exert a greater torque on the lug nut, and hopefully you’ll be able to get the nut off! If not, what can you do? Consider that you have two options: 1) increase magnitude of force 2) increase th ...
... At which point, A or B, would you push? Clearly that would be point A. Why? Because you know that you can exert a greater torque on the lug nut, and hopefully you’ll be able to get the nut off! If not, what can you do? Consider that you have two options: 1) increase magnitude of force 2) increase th ...
Examples of Inertia
... continue to move forward even when the car has stopped • The reason it is harder to push a wheelbarrow full of bricks rather than an empty one • Inertia is the reason it is harder to stop a big truck going 55 mph than a small car going 55 mph ...
... continue to move forward even when the car has stopped • The reason it is harder to push a wheelbarrow full of bricks rather than an empty one • Inertia is the reason it is harder to stop a big truck going 55 mph than a small car going 55 mph ...
PowerPoints
... – Example: if the acceleration is along the direction of motion, the speed grows by the same amount in each time interval (e.g., second) – if the speed changes by 1 meter per second each second, the acceleration is (1 meter per second) per second, or 1 m/s2. if v = 15 m/s at time t = 0, and a = 1 m/ ...
... – Example: if the acceleration is along the direction of motion, the speed grows by the same amount in each time interval (e.g., second) – if the speed changes by 1 meter per second each second, the acceleration is (1 meter per second) per second, or 1 m/s2. if v = 15 m/s at time t = 0, and a = 1 m/ ...
Force
... A person weighs a fish on a spring scale attached to the ceiling of an elevator, as shown in Figure 4.14. Show that if the elevator accelerates, the spring scale reads an apparent weight different from the fish’s true weight. ...
... A person weighs a fish on a spring scale attached to the ceiling of an elevator, as shown in Figure 4.14. Show that if the elevator accelerates, the spring scale reads an apparent weight different from the fish’s true weight. ...
Advanced Higher Physics learning outcomes
... State that the angular acceleration produced by an unbalanced torque depends on the moment of inertia of the object. Explain that the moment of inertia of an object depends on the mass of the object and the distribution of the mass about a fixed axis. Carry out calculations involving moment of inert ...
... State that the angular acceleration produced by an unbalanced torque depends on the moment of inertia of the object. Explain that the moment of inertia of an object depends on the mass of the object and the distribution of the mass about a fixed axis. Carry out calculations involving moment of inert ...
IS 1 Motion Unit
... 2. Know that every object exerts gravitational force on every other object, and how this force depends on the masses of the objects and the distance between them. 3. Know that when one object exerts a force on a second object, the second object exerts a force of equal magnitude and in the opposite d ...
... 2. Know that every object exerts gravitational force on every other object, and how this force depends on the masses of the objects and the distance between them. 3. Know that when one object exerts a force on a second object, the second object exerts a force of equal magnitude and in the opposite d ...
Uniform Circular Motion
... For an object in UCM, what direction is the net force? The same direction as the acceleration – toward the center Fc = mac If you stop the acceleration, what direction will the object move? The movement of the object is in the direction of the velocity or tangent to the circle. ...
... For an object in UCM, what direction is the net force? The same direction as the acceleration – toward the center Fc = mac If you stop the acceleration, what direction will the object move? The movement of the object is in the direction of the velocity or tangent to the circle. ...
Newton's theorem of revolving orbits
In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.