Slide 1
... • Which has more momentum, a 0.046kilogram golf ball with a speed of 60.0 meters per second, or a 7.0-kilogram bowling ball with a speed of 6.0 meters per second? • Momentum golf ball = 0.046 kg x 60.0 m/s =2.8kg*m/s • Momentum bowling ball = 7.0 kg x 6.0 m/s = 42 kg*m/s ...
... • Which has more momentum, a 0.046kilogram golf ball with a speed of 60.0 meters per second, or a 7.0-kilogram bowling ball with a speed of 6.0 meters per second? • Momentum golf ball = 0.046 kg x 60.0 m/s =2.8kg*m/s • Momentum bowling ball = 7.0 kg x 6.0 m/s = 42 kg*m/s ...
Chapter 4 Slides
... • To learn to make free-body diagrams Copyright © 2012 Pearson Education Inc. ...
... • To learn to make free-body diagrams Copyright © 2012 Pearson Education Inc. ...
chapter05
... The medium exerts a resistive force, , on an object moving through the medium The magnitude of depends on the medium The direction of is opposite the direction of motion of the object relative to the medium nearly always increases with increasing speed ...
... The medium exerts a resistive force, , on an object moving through the medium The magnitude of depends on the medium The direction of is opposite the direction of motion of the object relative to the medium nearly always increases with increasing speed ...
Physics 2101, First Exam, Fall 2007
... The weight and the normal force are both in the vertical direction; if there is no friction a force F would be the only force with a horizontal component, and thus it will always produce an acceleration. 16. A ball with a weight of 1.5 N is thrown at an angle of 30◦ above the horizontal with an init ...
... The weight and the normal force are both in the vertical direction; if there is no friction a force F would be the only force with a horizontal component, and thus it will always produce an acceleration. 16. A ball with a weight of 1.5 N is thrown at an angle of 30◦ above the horizontal with an init ...
Chapter 10 Dynamics of Rotational Motion
... Here we include all forces including internal forces of nearby particles, but since (according to third law) such forces produces the same in magnitude and opposite in direction torques their overall effect is zero. Therefore the above equation can be rewritten as ...
... Here we include all forces including internal forces of nearby particles, but since (according to third law) such forces produces the same in magnitude and opposite in direction torques their overall effect is zero. Therefore the above equation can be rewritten as ...
Regular Note
... In this case, the static friction force spans the range from 0 Newton (if there is no force upon the box) to 25 Newton (if you push on the box with 25 Newton of force). ...
... In this case, the static friction force spans the range from 0 Newton (if there is no force upon the box) to 25 Newton (if you push on the box with 25 Newton of force). ...
Mark the following statements true or false
... satellite B is 6 hours. Therefore, from Kepler’s 3rd law, we can conclude that a. The speed of A is twice the speed of B b. A is closer to earth than is B c. B is closer to earth than is A d. The speed of B is greater than the speed of A e. A and B sweep out equal areas around the earth in equal tim ...
... satellite B is 6 hours. Therefore, from Kepler’s 3rd law, we can conclude that a. The speed of A is twice the speed of B b. A is closer to earth than is B c. B is closer to earth than is A d. The speed of B is greater than the speed of A e. A and B sweep out equal areas around the earth in equal tim ...
Chapter 6 notes
... • Force Pairs Do Not Act on the Same Object A force is always exerted by one object on another object. This rule is true for all forces, including action and reaction forces. • Action and reaction forces in a pair do not act on the same object. If they did, the net force would always be 0 N and noth ...
... • Force Pairs Do Not Act on the Same Object A force is always exerted by one object on another object. This rule is true for all forces, including action and reaction forces. • Action and reaction forces in a pair do not act on the same object. If they did, the net force would always be 0 N and noth ...
1 - sciencewithskinner
... Name ________________________________________________Date_______________Period__________ Newton’s 2nd & 3rd Laws of Motion (answer sheet) 1. Your weight is the result of the gravitational force of the earth on your body. Describe the corresponding reaction force. the gravitational force of your body ...
... Name ________________________________________________Date_______________Period__________ Newton’s 2nd & 3rd Laws of Motion (answer sheet) 1. Your weight is the result of the gravitational force of the earth on your body. Describe the corresponding reaction force. the gravitational force of your body ...
Newton's theorem of revolving orbits
In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.