Simple Harmonic Motion
... Cycle: One complete oscillation of the body. Period (T): The time (in s) for one complete cycle. Frequency (f): The number of complete cycles made per second (in Hertz or s-1). (Note: f = 1 / T) Angular frequency (ω): Also called angular speed, in circular motion this is a measure of the rate of rot ...
... Cycle: One complete oscillation of the body. Period (T): The time (in s) for one complete cycle. Frequency (f): The number of complete cycles made per second (in Hertz or s-1). (Note: f = 1 / T) Angular frequency (ω): Also called angular speed, in circular motion this is a measure of the rate of rot ...
Chapter 5 Lecture
... Doubling the force causes double the reading on the spring. When both forces are applied, the reading is three times the initial reading. ...
... Doubling the force causes double the reading on the spring. When both forces are applied, the reading is three times the initial reading. ...
![[2015 solutions]](http://s1.studyres.com/store/data/008881821_1-1b74810f90a341f17acc5dd8ebcca870-300x300.png)
[2015 solutions]
... (1) (a) Show that angular momentum is conserved by calculating Torque. (b) We have L2 mṙ2 Veff = ...
... (1) (a) Show that angular momentum is conserved by calculating Torque. (b) We have L2 mṙ2 Veff = ...
Forces Weight
... When an item is dropped, it accelerates towards the ground under the force of gravity. The acceleration of the object as it falls is equal to g, so a falling object has acceleration (a) given by a = 10 m/s2 We have established that g is 10 N/kg here on Earth but g is different when we go to other pl ...
... When an item is dropped, it accelerates towards the ground under the force of gravity. The acceleration of the object as it falls is equal to g, so a falling object has acceleration (a) given by a = 10 m/s2 We have established that g is 10 N/kg here on Earth but g is different when we go to other pl ...
Forces and Motion
... An object will remain at rest or in motion in a straight line at constant velocity (not accelerating) unless an UNBALANCED FORCE acts on the object. ...
... An object will remain at rest or in motion in a straight line at constant velocity (not accelerating) unless an UNBALANCED FORCE acts on the object. ...
MS-Word format
... trajectory with a downward acceleration of approximately vx2/L, from which the required normal force can be calculated as N = mg – mvx2/L. Note that the normal force is constant and less than mg throughout the circular portion of the trajectory and there is a value of vx at which N reaches zero. For ...
... trajectory with a downward acceleration of approximately vx2/L, from which the required normal force can be calculated as N = mg – mvx2/L. Note that the normal force is constant and less than mg throughout the circular portion of the trajectory and there is a value of vx at which N reaches zero. For ...
U9 WS 2 - Rollercoasters
... 3. A. If point B is 28 meters higher than point D, how fast must you be going at point D (Assume no energy is dissipated between B and D)? (hint: think energy!) ...
... 3. A. If point B is 28 meters higher than point D, how fast must you be going at point D (Assume no energy is dissipated between B and D)? (hint: think energy!) ...
Sample
... Topic: Newton's 1st Law 15) Whirl a rock at the end of a string and it follows a circular path. If the string breaks, the tendency of the rock is to A) continue to follow a circular path. B) follow a straight-line path. C) increase its speed. D) revolve in a smaller circle. Answer: B Diff: 1 Topic: ...
... Topic: Newton's 1st Law 15) Whirl a rock at the end of a string and it follows a circular path. If the string breaks, the tendency of the rock is to A) continue to follow a circular path. B) follow a straight-line path. C) increase its speed. D) revolve in a smaller circle. Answer: B Diff: 1 Topic: ...
HOMEWORK FOR UNIT 5-1
... if the relationship between widgets and doodads is a proportional one? Sketch on the axes on the right of the table what the graph would look like if widgets are proportional to doodads. Divide the number of widgets by the number of doodads in each case. If the ratio is more or less the same in each ...
... if the relationship between widgets and doodads is a proportional one? Sketch on the axes on the right of the table what the graph would look like if widgets are proportional to doodads. Divide the number of widgets by the number of doodads in each case. If the ratio is more or less the same in each ...
Newton's theorem of revolving orbits
In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.