Lecture-14-10
... pulsar is out of nuclear fuel, where does all this energy come from ? • The angular speed of the pulsar, and so the rotational kinetic energy, is going down over time. This kinetic energy is converted into the energy coming out of that star. • calculate the change in rotational kinetic energy from t ...
... pulsar is out of nuclear fuel, where does all this energy come from ? • The angular speed of the pulsar, and so the rotational kinetic energy, is going down over time. This kinetic energy is converted into the energy coming out of that star. • calculate the change in rotational kinetic energy from t ...
6-1 Gravity and Motion
... object to resist change in its motion • The greater the mass the greater the inertia • The greater the velocity the greater the inertia ...
... object to resist change in its motion • The greater the mass the greater the inertia • The greater the velocity the greater the inertia ...
Sample Unit – Physics – Year 11
... Newton’s first and second law can be applied to evaluate forces at points of the structure. Examine dynamic examples such as cars in motion to evaluate the role of the motor in overcoming friction to maintain a constant velocity. Apply previous knowledge of vector components into analysing examples ...
... Newton’s first and second law can be applied to evaluate forces at points of the structure. Examine dynamic examples such as cars in motion to evaluate the role of the motor in overcoming friction to maintain a constant velocity. Apply previous knowledge of vector components into analysing examples ...
Lecture Notes for Sections 14.1
... particles can be derived by integrating the equation of motion (F = ma) with respect to displacement. By substituting at = v (dv/ds) into Ft = mat, the result is integrated to yield an equation known as the principle of work and energy. This principle is useful for solving problems that involve forc ...
... particles can be derived by integrating the equation of motion (F = ma) with respect to displacement. By substituting at = v (dv/ds) into Ft = mat, the result is integrated to yield an equation known as the principle of work and energy. This principle is useful for solving problems that involve forc ...
6/11 Erwin Sitompul University Physics: Mechanics
... Out of common experience, we know that any change in velocity must be due to an interaction between an object (a body) and something in its surroundings. An interaction that can cause an acceleration of a body is called a force. Force can be loosely defined as a push or pull on the body. The r ...
... Out of common experience, we know that any change in velocity must be due to an interaction between an object (a body) and something in its surroundings. An interaction that can cause an acceleration of a body is called a force. Force can be loosely defined as a push or pull on the body. The r ...
Forces and Motion
... and opposite force on the first object • Momentum – Product of an object’s mass and its velocity – Objects momentum at rest is zero – Unit kg m/s ...
... and opposite force on the first object • Momentum – Product of an object’s mass and its velocity – Objects momentum at rest is zero – Unit kg m/s ...
Lab Writeup Moment of Inertia
... If we apply a single, unbalanced force, F, to an object, the object will undergo linear acceleration, a, which is determined by the force and the mass, m, of the object. The mass is a measure of the object’s resistance to changing velocity, its inertia. This relationship is written F ma . If we ...
... If we apply a single, unbalanced force, F, to an object, the object will undergo linear acceleration, a, which is determined by the force and the mass, m, of the object. The mass is a measure of the object’s resistance to changing velocity, its inertia. This relationship is written F ma . If we ...
CTE3-Script.pdf
... The term on the left hand side is the product of mass times acceleration. The first three terms on the right hand side are the mutual interaction forces among particles of the body. Specifically, σxy is the component of the stress tensor representing force along the x direction acting on a plane who ...
... The term on the left hand side is the product of mass times acceleration. The first three terms on the right hand side are the mutual interaction forces among particles of the body. Specifically, σxy is the component of the stress tensor representing force along the x direction acting on a plane who ...
v - Personal.psu.edu
... The effect of an external force is to change the momentum of the entire system. If the external force is zero the system maintains a zero or constant velocity and the total momentum of the system is conserved ...
... The effect of an external force is to change the momentum of the entire system. If the external force is zero the system maintains a zero or constant velocity and the total momentum of the system is conserved ...
Simple Harmonic Motion
... Simple Harmonic Motion Definitions of Terms • Amplitude = A = the maximum displacement of the moving object from its equilibrium position. • (unit = m) • Period = T = the time it takes the object to complete one full cycle of motion. • (unit = s) • Frequency = f = the number of cycles or vibration ...
... Simple Harmonic Motion Definitions of Terms • Amplitude = A = the maximum displacement of the moving object from its equilibrium position. • (unit = m) • Period = T = the time it takes the object to complete one full cycle of motion. • (unit = s) • Frequency = f = the number of cycles or vibration ...
Impulse Momentum (Problem and Solutions) 1. An object travels
... Impulse Momentum (Problem and Solutions) 1. An object travels with a velocity 4m/s to the east. Then, its direction of motion and magnitude of velocity are changed. Picture given below shows the directions and magnitudes of velocities. Find the impulse given to this object. ...
... Impulse Momentum (Problem and Solutions) 1. An object travels with a velocity 4m/s to the east. Then, its direction of motion and magnitude of velocity are changed. Picture given below shows the directions and magnitudes of velocities. Find the impulse given to this object. ...
Sample problems
... A) 5 s B) 10 s C) 15 s D) 20 s E) 25 s 4. An object dropped from the window of a tall building hits the ground in12.0 s. If its acceleration is 9.8 m/ s 2, the height of the window above the ground is : A) 29.4 m B) 58.8 m C) 118 m D) 353 m E) 706 m 5. The angle between vectors A = 4 i – 3 j and B = ...
... A) 5 s B) 10 s C) 15 s D) 20 s E) 25 s 4. An object dropped from the window of a tall building hits the ground in12.0 s. If its acceleration is 9.8 m/ s 2, the height of the window above the ground is : A) 29.4 m B) 58.8 m C) 118 m D) 353 m E) 706 m 5. The angle between vectors A = 4 i – 3 j and B = ...
General Physics (PHY 2130)
... Example: Find the tension in the cord connecting the two blocks as shown. A force of 10.0 N is applied to the right on block 1. Assume a frictionless surface. The masses are m1 = 3.00 kg and m2 = 1.00 kg. ...
... Example: Find the tension in the cord connecting the two blocks as shown. A force of 10.0 N is applied to the right on block 1. Assume a frictionless surface. The masses are m1 = 3.00 kg and m2 = 1.00 kg. ...
