sample exam 1 - PhysicsEducation.net
... be uniform throughout. You find that a particle with a 3-C charge, placed 1 m from the center of the room, experiences a force of 18 N in the direction of north. After you leave, taking your particle with you, someone else enters the room and makes force measurements on a particle with a charge of – ...
... be uniform throughout. You find that a particle with a 3-C charge, placed 1 m from the center of the room, experiences a force of 18 N in the direction of north. After you leave, taking your particle with you, someone else enters the room and makes force measurements on a particle with a charge of – ...
Chris Khan 2008 Physics Chapter 9 Linear momentum is defined as
... When dropping an item, the momentum before hitting the floor is –mv since the velocity is in the negative y-direction. If the item lands on the floor, final momentum is 0. If the item bounces, the final momentum is mv. o When dropping a beanbag, ∆P = Pf – Pi = 0 – m(-v) = mv. o When dropping a rubbe ...
... When dropping an item, the momentum before hitting the floor is –mv since the velocity is in the negative y-direction. If the item lands on the floor, final momentum is 0. If the item bounces, the final momentum is mv. o When dropping a beanbag, ∆P = Pf – Pi = 0 – m(-v) = mv. o When dropping a rubbe ...
Midterms: Place, Rules, How to study
... PLACE AND TIME: Friday, September 16 we have the first midterm, covering Units 1-6. All midterms will be during regular class hours but will take place in the S Beh auditorium which is located south of the Marriott Library - check it out on the campus map. If possible, please be there at least 5 min ...
... PLACE AND TIME: Friday, September 16 we have the first midterm, covering Units 1-6. All midterms will be during regular class hours but will take place in the S Beh auditorium which is located south of the Marriott Library - check it out on the campus map. If possible, please be there at least 5 min ...
Phys 2102 Spring 2002 - LSU Physics & Astronomy
... Calculate the Force (a Vector!) In Each Case Using Coulomb’s Law and Finally Add All the ...
... Calculate the Force (a Vector!) In Each Case Using Coulomb’s Law and Finally Add All the ...
Document
... Newton’s Second Law of Motion » The second law says that the acceleration of an object produced by a force is directly proportional to the magnitude of the force, the same direction as the force, and inversely proportional to the mass of the object. ...
... Newton’s Second Law of Motion » The second law says that the acceleration of an object produced by a force is directly proportional to the magnitude of the force, the same direction as the force, and inversely proportional to the mass of the object. ...
Lecture 2c - Newton`s Laws & Applications
... is zero, it will remain either at rest or moving in a straight line at constant speed. • Newton’s second law: • Newton’s third law: • Weight is the gravitational force on an object. • Free-body diagrams are essential for problemsolving. Do one object at a time, make sure you have all the forces, pic ...
... is zero, it will remain either at rest or moving in a straight line at constant speed. • Newton’s second law: • Newton’s third law: • Weight is the gravitational force on an object. • Free-body diagrams are essential for problemsolving. Do one object at a time, make sure you have all the forces, pic ...
The Law of Conservation of Mechanical Energy
... Thus impulse has units of kg m/s OR Ns Questions on Momentum and Impulse Question 1 (To be solved in class) a. Find the momentum of an automobile of mass 1350 kg travelling at 20 m/s b. Find the momentum of an automobile of mass 1350 kg travelling at 65 km/h c. A vehicle travelling at 30 m/s possess ...
... Thus impulse has units of kg m/s OR Ns Questions on Momentum and Impulse Question 1 (To be solved in class) a. Find the momentum of an automobile of mass 1350 kg travelling at 20 m/s b. Find the momentum of an automobile of mass 1350 kg travelling at 65 km/h c. A vehicle travelling at 30 m/s possess ...
r - TTU Physics
... reference frame of the relative coordinate r (of the “particle” of “mass” μ) is not an inertial frame! – Its not a force in the Newtonian sense! (It doesn’t come from any interaction of the “mass” μ with its environment!) It’s a part of the “μa” (right!) of Newton’s 2nd Law, rewritten to appear on t ...
... reference frame of the relative coordinate r (of the “particle” of “mass” μ) is not an inertial frame! – Its not a force in the Newtonian sense! (It doesn’t come from any interaction of the “mass” μ with its environment!) It’s a part of the “μa” (right!) of Newton’s 2nd Law, rewritten to appear on t ...
Document
... Uniform Circular Motion (Cont.) The question of an outward force can be resolved by asking what happens when the string breaks! Ball moves tangent to v path, NOT outward as might be expected. When central force is removed, ball continues in straight line. Centripetal force is needed to change direc ...
... Uniform Circular Motion (Cont.) The question of an outward force can be resolved by asking what happens when the string breaks! Ball moves tangent to v path, NOT outward as might be expected. When central force is removed, ball continues in straight line. Centripetal force is needed to change direc ...
Friction - Hicksville Public Schools / Homepage
... less weight(person) = less gravity(moon) x same mass(person) Why? Moon ~ less mass, less gravity Earth ~ more mass, more gravity (10x Moon) ...
... less weight(person) = less gravity(moon) x same mass(person) Why? Moon ~ less mass, less gravity Earth ~ more mass, more gravity (10x Moon) ...
steady state solution
... Be able to obtain an additional moment balance equation for a rigid body moving without rotation or rotating about a fixed axis at constant rate. Be able to use Newton’s laws of motion to solve for unknown accelerations or forces in a system of particles Use Newton’s laws of motion to derive differe ...
... Be able to obtain an additional moment balance equation for a rigid body moving without rotation or rotating about a fixed axis at constant rate. Be able to use Newton’s laws of motion to solve for unknown accelerations or forces in a system of particles Use Newton’s laws of motion to derive differe ...
Wednesday, Oct. 29, 2008
... The principle of energy conservation can be used to solve problems that are harder to solve just using Newton’s laws. It is used to describe motion of an object or a system of objects. A new concept of linear momentum can also be used to solve physical problems, especially the problems involving col ...
... The principle of energy conservation can be used to solve problems that are harder to solve just using Newton’s laws. It is used to describe motion of an object or a system of objects. A new concept of linear momentum can also be used to solve physical problems, especially the problems involving col ...
