Honors Physics
... There is a point along the line joining the center of the earth to the center of the moon at which the two gravitational forces cancel. Find this point’s distance, x, from the earth’s center. Use D for the earthmoon distance, and me and mm for the masses of earth and moon respectively. ...
... There is a point along the line joining the center of the earth to the center of the moon at which the two gravitational forces cancel. Find this point’s distance, x, from the earth’s center. Use D for the earthmoon distance, and me and mm for the masses of earth and moon respectively. ...
Sections 14.1-14.3 - University of Mary Hardin–Baylor
... U1-2 is the work done by all the forces acting on the particle as it moves from point 1 to point 2. Work can be either a positive or negative scalar. T1 and T2 are the kinetic energies of the particle at the initial and final position, respectively. Thus, T1 = 0.5 m (v1)2 and T2 = 0.5 m (v2)2. The ...
... U1-2 is the work done by all the forces acting on the particle as it moves from point 1 to point 2. Work can be either a positive or negative scalar. T1 and T2 are the kinetic energies of the particle at the initial and final position, respectively. Thus, T1 = 0.5 m (v1)2 and T2 = 0.5 m (v2)2. The ...
3.5 Notes – Special Case 2: Circular Motion Q: What determines
... velocity and position vectors have to remain mutually perpendicular for there to be uniform circular motion. If not, you would get a speeding up-slowing down effect, which would then affect your change in position, accordingly. 3. The maintenance of ∆θ means that you have isosceles triangles for bot ...
... velocity and position vectors have to remain mutually perpendicular for there to be uniform circular motion. If not, you would get a speeding up-slowing down effect, which would then affect your change in position, accordingly. 3. The maintenance of ∆θ means that you have isosceles triangles for bot ...
Forces and Motion Jeopardy
... On a speed-time graph, a flat line represents ___________ acceleration. ...
... On a speed-time graph, a flat line represents ___________ acceleration. ...
Conservation of Mechanical Energy Law of Conservation of Energy
... Conservation of Energy: The SUM of ALL energies remains constant. The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and from one body to another, but the total amount remains constant. ...
... Conservation of Energy: The SUM of ALL energies remains constant. The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and from one body to another, but the total amount remains constant. ...
Newton`s Laws of Motion - Madison County Schools
... Because of inertia, objects (including you) resist changes in their motion. When the car going 80 km/hour is stopped by the brick wall, your body keeps moving at 80 m/hour. ...
... Because of inertia, objects (including you) resist changes in their motion. When the car going 80 km/hour is stopped by the brick wall, your body keeps moving at 80 m/hour. ...
force problem set 1: 2/17/12
... 18. Refer back to the box in question 15. Which of the following could possibly be the velocity of the box? A. 8.5m/s B. 2.2m/s C. 16m/s D. 0m/s 19. What is the mass of a cannon projectile that is accelerated at 120m/s/s by a 12000N force? 20. What is the mass of a cart that is accelerated at 3.0m/s ...
... 18. Refer back to the box in question 15. Which of the following could possibly be the velocity of the box? A. 8.5m/s B. 2.2m/s C. 16m/s D. 0m/s 19. What is the mass of a cannon projectile that is accelerated at 120m/s/s by a 12000N force? 20. What is the mass of a cart that is accelerated at 3.0m/s ...
answers
... The larger, flatter object will create more air resistance. The flatness of the object will catch more air than the less flat object. Choose the term from the word list that best completes each statement. Write the term in the blank at the left of each statement. action gravity mass ...
... The larger, flatter object will create more air resistance. The flatness of the object will catch more air than the less flat object. Choose the term from the word list that best completes each statement. Write the term in the blank at the left of each statement. action gravity mass ...
Rotational Motion
... A one piece cylinder has a core section that protrudes from a larger drum. A rope wrapped around the large drum of radius, R, exerts a force, F1, to the right, while a rope wrapped around the core, radius r, exerts a force, F2 downward.. Calculate the net torque, in variables. If F1=5 N, R = 1 m, F2 ...
... A one piece cylinder has a core section that protrudes from a larger drum. A rope wrapped around the large drum of radius, R, exerts a force, F1, to the right, while a rope wrapped around the core, radius r, exerts a force, F2 downward.. Calculate the net torque, in variables. If F1=5 N, R = 1 m, F2 ...
Gravitation Worksheet
... 1. The reason the Moon does not fall down and collide with the Earth is because (a) It is being pulled by the Sun and planets as well as by Earth. (b) The net force on it is zero. (c) It is beyond the main pull of Earth’s gravity. (d) None of the above. Answer (d): With no net force the earth would ...
... 1. The reason the Moon does not fall down and collide with the Earth is because (a) It is being pulled by the Sun and planets as well as by Earth. (b) The net force on it is zero. (c) It is beyond the main pull of Earth’s gravity. (d) None of the above. Answer (d): With no net force the earth would ...
Newton`s Laws of Motion
... • Weight will change based on local gravity; NASA has to take this into effect ...
... • Weight will change based on local gravity; NASA has to take this into effect ...
PWE 16-5: Determining Charge-to
... The only force that acts on the particle is the electric force given by Equation 16-2. Since the particle accelerates in the direction of the s, the force on the particle must electric field E s. So the charge on also be in the direction of E s is uniform the particle must be positive. Since E (it h ...
... The only force that acts on the particle is the electric force given by Equation 16-2. Since the particle accelerates in the direction of the s, the force on the particle must electric field E s. So the charge on also be in the direction of E s is uniform the particle must be positive. Since E (it h ...
Sport Application and Newton`s Laws of Motion
... power impressed, and is made in the direction of the right(straight) line in which the force is impressed. • Or • If a body of mass(m) has an acceleration(a), the force acting on it is (f), defined as the product of its mass and acceleration (F=ma) • Law of Acceleration-the acceleration of an object ...
... power impressed, and is made in the direction of the right(straight) line in which the force is impressed. • Or • If a body of mass(m) has an acceleration(a), the force acting on it is (f), defined as the product of its mass and acceleration (F=ma) • Law of Acceleration-the acceleration of an object ...
Forces and the Laws of Motion Section 3
... •Objects at rest stay at rest and objects in motion stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force. (also called the law of inertia). ...
... •Objects at rest stay at rest and objects in motion stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force. (also called the law of inertia). ...
PHYS 243, Exam 1
... (b) only in inertial reference frames (c) only in noninertial reference frames (d) only in reference frames that are at rest _______9. The velocity versus time graph for a moving object is a straight line whose slope is negative and it crosses the t-axis at 5.0 sec. We can conclude that the object’s ...
... (b) only in inertial reference frames (c) only in noninertial reference frames (d) only in reference frames that are at rest _______9. The velocity versus time graph for a moving object is a straight line whose slope is negative and it crosses the t-axis at 5.0 sec. We can conclude that the object’s ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.