
Slide 1
... stops, you continue moving forward. When the stopped train starts moving again, you remain stationary and are thrown backwards. In both cases, it’s due to your inertia. ...
... stops, you continue moving forward. When the stopped train starts moving again, you remain stationary and are thrown backwards. In both cases, it’s due to your inertia. ...
sept19
... Force on the planets depends on distance The higher the speed an object moves in a circle the greater acceleration and the force needed to hold it in that circle. The force on the planets closest to the Sun has to be greater than that on the planets farther away. ...
... Force on the planets depends on distance The higher the speed an object moves in a circle the greater acceleration and the force needed to hold it in that circle. The force on the planets closest to the Sun has to be greater than that on the planets farther away. ...
01-4-momentum-with
... • applies to each component of momentum • net force is due to interactions of the system with the surroundings • time interval is the duration of the interaction • product of net force times the time interval is called impulse • if no interaction, momentum of the system is constant ...
... • applies to each component of momentum • net force is due to interactions of the system with the surroundings • time interval is the duration of the interaction • product of net force times the time interval is called impulse • if no interaction, momentum of the system is constant ...
Electromagnetic Force
... A wire 1.0m long carries 0.50amps of current. If the force acting on the wire is 0.2N, what is the magnetic field strength the wire experiences? F=BIL 0.20N = B(0.5Amp)(1.0m) B = 0.40 N/A∙m ...
... A wire 1.0m long carries 0.50amps of current. If the force acting on the wire is 0.2N, what is the magnetic field strength the wire experiences? F=BIL 0.20N = B(0.5Amp)(1.0m) B = 0.40 N/A∙m ...
Vectors & Scalars - The Grange School Blogs
... Starting from rest a car travels for 2 minutes with a uniform acceleration of 0.3 ms-2 after which its speed is kept constant until the car is brought to rest with a uniform retardation of 0.6ms-2 if the total distance travelled is 4500m how long did the journey take? Initial acceleration time = 2 m ...
... Starting from rest a car travels for 2 minutes with a uniform acceleration of 0.3 ms-2 after which its speed is kept constant until the car is brought to rest with a uniform retardation of 0.6ms-2 if the total distance travelled is 4500m how long did the journey take? Initial acceleration time = 2 m ...
force
... Why is a heavy truck harder to stop than a small moving car at the same speed? - truck has a greater mass, therefore greater momentum Can you change an objects momentum? - Yes, using forces, but most importantly “how long” that force is applied ex. force applied briefly to a stalled car, small c ...
... Why is a heavy truck harder to stop than a small moving car at the same speed? - truck has a greater mass, therefore greater momentum Can you change an objects momentum? - Yes, using forces, but most importantly “how long” that force is applied ex. force applied briefly to a stalled car, small c ...
Worksheet - 3 - Force of Friction.jnt
... 9) A 950 kg car traveling at a constant velocity of 28 m/s, has a coefficient of friction of 0.125 acting on its axle. How much force is required by the engine to maintain its speed? ...
... 9) A 950 kg car traveling at a constant velocity of 28 m/s, has a coefficient of friction of 0.125 acting on its axle. How much force is required by the engine to maintain its speed? ...
reaction force.
... Describe how to identify a pair of action-reaction forces. Explain why the accelerations caused by an action force and a reaction force do not have to be equal. Explain why an action force is not cancelled by a reaction force. Explain how a horse-cart system accelerates. Explain what must occur in e ...
... Describe how to identify a pair of action-reaction forces. Explain why the accelerations caused by an action force and a reaction force do not have to be equal. Explain why an action force is not cancelled by a reaction force. Explain how a horse-cart system accelerates. Explain what must occur in e ...
Harmonic notes
... maximum value. This is because the velocity of the system is zero. This will occur when the displacement is equal to the amplitude. Once the mass is moving away from maximum displacement, some of the potential energy is converted to kinetic energy. The kinetic energy increases and the potential ener ...
... maximum value. This is because the velocity of the system is zero. This will occur when the displacement is equal to the amplitude. Once the mass is moving away from maximum displacement, some of the potential energy is converted to kinetic energy. The kinetic energy increases and the potential ener ...
The Milky Way - Computer Science Technology
... 1. A body continues at rest or in uniform motion in a straight line unless acted upon by some net force. An astronaut floating in space will continue to float forever in a straight line unless some external force is accelerating him/her. ...
... 1. A body continues at rest or in uniform motion in a straight line unless acted upon by some net force. An astronaut floating in space will continue to float forever in a straight line unless some external force is accelerating him/her. ...
Notes: Vectors
... A. Frame of reference is a point (origin) that an object's motion can be compared to. B. The origin can be moving (inertial frame of reference) as long as it is not accelerating. C. Motion can be measured relative to the origin using an x, y, z coordinate system (we will only work with the x and y a ...
... A. Frame of reference is a point (origin) that an object's motion can be compared to. B. The origin can be moving (inertial frame of reference) as long as it is not accelerating. C. Motion can be measured relative to the origin using an x, y, z coordinate system (we will only work with the x and y a ...
Newton’s Laws of Motion
... Example: You need to move a box of books into your dormitory room. To do so, you attach a rope to the box and pull on it with a force of 90.0 N at an angle of 30.0. The box of books has a mass of 20.0 kg, and the coefficient of friction between the bottom of the box and the hallway surface is 0.50 ...
... Example: You need to move a box of books into your dormitory room. To do so, you attach a rope to the box and pull on it with a force of 90.0 N at an angle of 30.0. The box of books has a mass of 20.0 kg, and the coefficient of friction between the bottom of the box and the hallway surface is 0.50 ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.