
PAP Work and Energy Notes
... further you stretch, the more force it requires EPE = ½ kx2 k = spring constant (N/m) x = distance spring is stretched or compressed from its natural length In all cases looked at – PE is stored energy that can be used later [examples #27 together, #28 on own, #29 HW] Mechanical Energy = KE + PE Ene ...
... further you stretch, the more force it requires EPE = ½ kx2 k = spring constant (N/m) x = distance spring is stretched or compressed from its natural length In all cases looked at – PE is stored energy that can be used later [examples #27 together, #28 on own, #29 HW] Mechanical Energy = KE + PE Ene ...
Lesson 44: Acceleration, Velocity, and Period in SHM
... ● Remember that in the examples above the mass has just been released from rest, so its velocity starts at zero. ● As it accelerates back to the equilibrium point, the elastic potential energy that was stored in the spring is converted to kinetic energy as the mass goes faster and faster. ● At the e ...
... ● Remember that in the examples above the mass has just been released from rest, so its velocity starts at zero. ● As it accelerates back to the equilibrium point, the elastic potential energy that was stored in the spring is converted to kinetic energy as the mass goes faster and faster. ● At the e ...
Rigid Body - Kinematics
... are talking about the coordinate axes Observed in the space coordinates, any point r on the body moves by dr = d Φn × r = dΩ × r Sign opposite from last lecture because the rotation is CCW ...
... are talking about the coordinate axes Observed in the space coordinates, any point r on the body moves by dr = d Φn × r = dΩ × r Sign opposite from last lecture because the rotation is CCW ...
Conceptual Questions
... 8. If the net work done on an object is positive, then the object's kinetic energy A) decreases. B) remains the same. C) increases. D) is zero. 9. If the net work done on an object is negative, then the object's kinetic energy A) decreases. B) remains the same. C) increases. D) is zero. 10. If the n ...
... 8. If the net work done on an object is positive, then the object's kinetic energy A) decreases. B) remains the same. C) increases. D) is zero. 9. If the net work done on an object is negative, then the object's kinetic energy A) decreases. B) remains the same. C) increases. D) is zero. 10. If the n ...
Math 256 Project
... At perihelion on February 9, 1986, Halley’s Comet was only 0.587 AU from the Sun, well inside the orbit of Venus. The comet was moving at − 11.53205 AU/y at that point. This is a negative number since the comet moves in retrograde motion (backwards). The average period of the comet's orbit is 76 yea ...
... At perihelion on February 9, 1986, Halley’s Comet was only 0.587 AU from the Sun, well inside the orbit of Venus. The comet was moving at − 11.53205 AU/y at that point. This is a negative number since the comet moves in retrograde motion (backwards). The average period of the comet's orbit is 76 yea ...
Newton`s Second Law and the Hydrostatic Relation
... balance each other, producing no vertical acceleration. The situation in which these two forces exactly balance each other is called hydrostatic balance. The equation above, which expresses this condition mathematically, is one form of the hydrostatic equation. In general, exact hydrostatic balance ...
... balance each other, producing no vertical acceleration. The situation in which these two forces exactly balance each other is called hydrostatic balance. The equation above, which expresses this condition mathematically, is one form of the hydrostatic equation. In general, exact hydrostatic balance ...
Advanced Placement C Physics – Course Guide
... a. Students should understand the technique for finding center of mass so they can: (1) Identify by inspection the center of mass of a body that has a point of symmetry. (2) Locate the center of mass of a system consisting of two such bodies. (3) Use integration to find the center of mass of a thin ...
... a. Students should understand the technique for finding center of mass so they can: (1) Identify by inspection the center of mass of a body that has a point of symmetry. (2) Locate the center of mass of a system consisting of two such bodies. (3) Use integration to find the center of mass of a thin ...
8 - cloudfront.net
... F. A different ball, also with a mass of 7 kg, has been falling under the influence of air resistance, when you happen to notice it. At the time that you notice it, it is falling with a CONSTANT VELOCITY. Solve for any forces acting on the bowling ball. Fg = 70 N, Fair = 70 N 6. Given the pulley sys ...
... F. A different ball, also with a mass of 7 kg, has been falling under the influence of air resistance, when you happen to notice it. At the time that you notice it, it is falling with a CONSTANT VELOCITY. Solve for any forces acting on the bowling ball. Fg = 70 N, Fair = 70 N 6. Given the pulley sys ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.